OK, lets look at what you have proposed.GARY C wrote:That part I understand but thanks for laying out the math for better explanation.
I think I failed to explain properly what I was thinking.
If you have 2 springs with 250 lbs seat pressure which is what everyone seems to focus on but one has a 500 spring rate and the other has a 650 spring rate, even though they both have the same seat pressure the 650 rate spring will greatly increase side load and ware. I hope that makes since.
If both springs produce 250 lbs seat FORCE, then the 500 lb/in spring must deflect .5" at installed height, and the 650 lb/in spring must deflect .385" at installed height.
If both have the same valve lift (0.5"), the 500 lb/in spring will produce a nose FORCE of 500 lbs, and the 650 lb/in spring will result in a nose FORCE of 575 lbs.
The side force produced is a function of FORCE, friction coefficient, and pressure angle. Assuming both have identical Mu values and pressure angles, then the side FORCE is determined only by the nose FORCES; 500 and 575 lbs.
Therefore the 650 lb/in spring will result in a side force that is 15% greater (575/500) than the 500 lb/in spring.
But wear is not just a function of load; the surface area of the roller follower must be considered. The area of contact between two rollers is a function of material deflection, diameters, and roller width. If the materials, diameters, and roller widths are the same, then the side force is once again the result of nose FORCES.